Q. A source of sound of frequency 500 Hz is moving towards an observer with velocity $30ms^{- 1}$.The speed of sound is $330ms^{- 1}$.The frequency heard by the observer will be

A) 545 Hz
B) 580 Hz
C) 558.3 Hz
D) 550 Hz
Explanation

(d) $v^{'} = \frac{u \times v}{u - u_{s}}$
$= \frac{330 \times 500}{330 - 30} = 550\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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