Q. A hollow cylinder with both sides open generates a frequency v in air. When the cylinder vertically immersed into water by half its length the frequency will be
A) V
B) 2v
C) v/2
D) v/4
Explanation
(a) $(i)\ Here,\ \frac{\lambda}{2} = l \Longrightarrow \lambda = 2l$
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So, $v_{1} = \frac{v}{2l}$
$(ii)and\frac{\lambda}{4} = \frac{l}{2}\ $
$\lambda = \frac{4\lambda}{2} = 2l$
$\therefore v_{2} = \frac{v}{2l},\ the\ same$
$\therefore(original)is\ the\ frequency,$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.