Q. A railway engine whistling at a constant frequency moves with a constant speed. It goes past a stationary observer standing beside the railway track. The frequency $(n^{'})$of the sound heard by the observer is plotted against time $(t)$, which of the following best represents the resulting curve

A) [image:15_image20.emf]
B) [image:15_image21.emf]
C) [image:15_image22.emf]
D) [image:15_image23.emf]
Explanation

(d) It is known that Doppler’s effect depends on velocity not on distance. When the source is approaching the stationary observer, the apparent frequency heard by the observer is
$n^{'} = \frac{v \times n}{v - v_{s}} = constant$
But $n^{'} > n$.
When the source has crossed the observer, apparent frequency heard by the observer is
$n^{''} = \frac{v \times n}{v + v_{s}} = another\ constant$
But $n^{''} < n$.option (d) is correct.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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