Q. A sounding source of frequency 500 Hz moves towards a stationary observer with a velocity$30\ ms^{- 1}$. If the velocity of sound in air is $330\ ms^{- 1}$, find frequency heard by the observer.

A) 500 Hz
B) 550 Hz
C) 355 Hz
D) 55.5 Hz
Explanation

(b) Here, v=500 Hz,$v_{o} - o$
$v_{s} = 30ms^{- 1},\ v = 330ms^{- 1}$
From ,
$v^{'} = v\left( \frac{v - v_{o}}{v - v_{s}} \right) = 500\left( \frac{300}{330 - 30} \right) = 550Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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