Q.
The displacement of the interfering sound waves are $y_{1} = 4\sin{\omega t}$ and $y_{2} = 3\sin{\left( \omega t + \frac{\pi}{2} \right).}$ What is the amplitude of the resultant wave
A) 5
B) 7
C) 1
D) 0
Explanation
(a) Since $\phi = \frac{\pi}{2} \Rightarrow A = \sqrt{a_{1}^{2} + a_{2}^{2}} = \sqrt{(4)^{2} + (3)^{2}} = 5$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.