Two sound waves (expressed in CGS units) given by $y_{1} = 0.3\sin{\frac{2\pi}{\lambda}(vt - x)}$ and $y_{2} = 0.4\sin{\frac{2\pi}{\lambda}(vt - x + heta)}$ interfere. The resultant amplitude at a place where phase difference is $\pi/2$ will be

Question

Two sound waves (expressed in CGS units) given by $y_{1} = 0.3\sin{\frac{2\pi}{\lambda}(vt - x)}$ and $y_{2} = 0.4\sin{\frac{2\pi}{\lambda}(vt - x + 	heta)}$ interfere. The resultant amplitude at a place where phase difference is $\pi/2$ will be

Dr. Abubacker · Accepted Answer

(c) Resultant amplitude$\  = \sqrt{a_{1}^{2} + a_{2}^{2} + 2a_{1}a_{2}\cos\phi}$
$= \sqrt{{0.3}^{2} + {0.4}^{2} + 2 	imes 0.3 	imes 0.4 	imes \cos\frac{\pi}{2}} = 0.5\ cm$

Q. Two sound waves (expressed in CGS units) given by $y_{1} = 0.3\sin{\frac{2\pi}{\lambda}(vt - x)}$ and $y_{2} = 0.4\sin{\frac{2\pi}{\lambda}(vt - x + \theta)}$ interfere. The resultant amplitude at a place where phase difference is $\pi/2$ will be

Explanation

Reviewed by Dr. Abubacker

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