Q. The length of a sonometer wire AB is 110 cm. Where should the two bridges be placed from A to divide the wire in three segments whose fundamental frequencies are in the ratio of 1:2:3

A) 30 cm, 90 cm
B) 60 cm, 90 cm
C) 40 cm, 70 cm
D) None of these
Explanation

(b) As $n_{1}:n_{2}:n_{3} = 1:2:3$
$\therefore\ \ \ \ \ \ \ \ l_{1}:l_{2}:l_{3} = \frac{1}{1}:\frac{1}{2}:\frac{1}{3} = 6:3:2$
Sum of the ratio $= 6 + 3 + 2 = 11$
$\therefore\ l_{1} = \frac{110}{11} \times 6 = 60cm,\ l_{2} = \frac{110}{11} \times 3 = 30cm$
$\therefore$ wedges should be placed from A at 60cm and 90cm.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Waves MCQs