(b) As $n_{1}:n_{2}:n_{3} = 1:2:3$
$\therefore\ \ \ \ \ \ \ \ l_{1}:l_{2}:l_{3} = \frac{1}{1}:\frac{1}{2}:\frac{1}{3} = 6:3:2$
Sum of the ratio $= 6 + 3 + 2 = 11$
$\therefore\ l_{1} = \frac{110}{11} \times 6 = 60cm,\ l_{2} = \frac{110}{11} \times 3 = 30cm$
$\therefore$ wedges should be placed from A at 60cm and 90cm.