Q. A tuning fork of frequency 512 Hz is used to produce vibrations in a sonometer wire of natural frequency 256 Hz. The wire will vibrate in
A) One segment
B) Two segments
C) Four segments
D) Three segments
Explanation
(b) As the wire is forced to have a frequency$= 512 = 2 \times 256 = 2n,$therefore, it must vibrate in two segments.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.