Q. A string fixed at both ends oscillates in 5 segments, length 10m and velocity of wave is$20\ ms^{- 1}$. What is the frequency?
A) 5 Hz
B) 15 Hz
C) 10 Hz
D) 2 Hz
Explanation
(a) Frequency of vibration is given by
$v = \frac{p}{2l}\sqrt{\frac{T}{m}}\ \ \ \ \left( where\ v = \sqrt{\frac{T}{m}} \right)$
$\therefore v = \frac{p}{2l}v = \frac{5 \times 20}{2 \times 10} = 5Hz\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.