Q. When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the velocity. The amplitude of wave is
A) λ
B) $\frac{\lambda}{2}$
C) $\frac{\lambda}{2\pi}$
D) $\frac{\lambda}{4\pi}$
Explanation
(c) Given, $v_{\max\ } = v$
$\Longrightarrow \ \ \ \ \ a\omega = v\ \ $
$\Longrightarrow a \times 2\pi v = v\lambda\ \ or\ a = \frac{\lambda}{2\pi}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.