(a) Comparing the given equation with standard equation
We get $\omega = 2\pi n = 200\pi \Rightarrow n = 100\ Hz$ and $k = \frac{20\pi}{17}$
$\because\lambda = \frac{2\pi}{k} = \frac{2\pi}{20\pi/17} = 1.7\ m$
And $v = \frac{\omega}{k} = \frac{200\pi}{20\pi/17} = 170\ m/s$