A whistle of frequency 540 Hz rerates in a horizontal circle of radius 2m at an angular speed of 15$rads^{- 1}$. The highest frequency heard by a listener at rest with respect to the center of circle (velocity of sound in air =$330ms^{- 1}$)

Question

Dr. Abubacker · Accepted Answer

(b) Velocity of source
$v_{s} = r\omega = 2 	imes 15 = 30ms^{- 1}$
The highest frequency heard by the stationary listener
$v^{'} = v\left( \frac{v}{v - v_{s}} ight)$
or$\ $
$v^{'} = 540\left( \frac{330}{330 - 30} ight) = 594\ Hz$

Q. A whistle of frequency 540 Hz rerates in a horizontal circle of radius 2m at an angular speed of 15$rads^{- 1}$. The highest frequency heard by a listener at rest with respect to the center of circle (velocity of sound in air =$330ms^{- 1}$)

Explanation

Reviewed by Dr. Abubacker

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