A $1\ cm$ long string vibrates with fundamental frequency of $256\ Hz.$ If the length is reduced to $\frac{1}{4}cm$ keeping the tension unaltered, the new fundamental frequency will be

Question

Dr. Abubacker · Accepted Answer

(d) $n \propto \frac{1}{l} \Rightarrow \frac{n_{2}}{n_{1}} = \frac{l_{1}}{l_{2}} \Rightarrow n_{2} = \frac{l_{1}}{l_{2}}n_{1} = \frac{1 	imes 256}{1/4} = 1024Hz$

Q. A $1\ cm$ long string vibrates with fundamental frequency of $256\ Hz.$ If the length is reduced to $\frac{1}{4}cm$ keeping the tension unaltered, the new fundamental frequency will be

Explanation

Reviewed by Dr. Abubacker

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