Q. A transverse progressive wave on a stretched string has a velocity of $10ms^{- 1}$ and a frequency of $100\ Hz.$ The phase difference between two particles of the string which are $2.5\ cm$ apart will be
A) $\pi/8$
B) $\pi/4$
C) $3\pi/8$
D) $\pi/2$
Explanation
(d) $v = n\lambda \Rightarrow \lambda = 10\ cm$
Phase difference $= \frac{2\pi}{\lambda} \times$ Path difference $= \frac{2\pi}{10} \times 2.5 = \frac{\pi}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.