(b) From the given equation amplitude $a = 0.04m$
Frequency $= \frac{Co - efficient\ of\ t}{2\pi} = \frac{\pi/5}{2\pi} = \frac{1}{10}Hz$
Wave length $\lambda = \frac{2\pi}{Co - efficient\ of\ x} = \frac{2\pi}{\pi/9} = 18m$
Wave speed $v = \frac{Co - efficient\ of\ t}{Co - efficient\ of\ x} = \frac{\pi/5}{\pi/9} = 1.8m/s$