Q. In stationary waves, distance between a node and its nearest antinode is $20\ cm.$ The phase difference between two particles having a separation of $60\ cm$ will be
A) Zero
B) $\pi/2$
C) $\pi$
D) $3\pi/2$
Explanation
(d) $\frac{\lambda}{4} = 20 \Rightarrow \lambda = 80cm,$ also $\Delta\phi = \frac{2\pi}{\lambda}.\Delta x$
$\Rightarrow \Delta\phi = \frac{60}{80} \times 2\pi = \frac{3\pi}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.