Q. The tension in a wire is decreased by 19%. The percentage decrease in frequency will be
A) 19%
B) 10%
C) 0.19%
D) None of these
Explanation
(b) $\frac{n_{2}}{n_{1}} = \sqrt{\frac{T_{2}}{T_{1}}} = \sqrt{\frac{81}{100}} = \frac{9}{10}$
$\therefore\left( \frac{n_{1} - n_{2}}{n_{1}} \right) \times 100 = 10\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.