Q. If the equation of transverse wave is y=sin (kx-2t), then the maximum particle velocity is
A) 4 unit
B) 2 unit
C) Zero
D) 6 unit
Explanation
(a) Equation of wave y=2 sin (kx-2t)
Comparing with standard equation
Y=a sin (kx-ωt)
a=2, ω=2
∴Maximum particle velocity
$v_{\max\ } = a\omega = 2 \times 2 \times 2 = 4\ unit$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.