If a source emitting waves a velocity $v/4\ $ and the observer moves away from the source with a velocity v/6, the apparent frequency as heard by the observer will be (v=velocity of sound)

Question

Dr. Abubacker · Accepted Answer

(c) When source and observer both are moving in the same direction and observer is ahead of source, then apparent frequency
$v^{'} = \frac{v - v_{o}}{v - v_{s}}v = \frac{v - \frac{v}{6}}{v - \frac{v}{4}} = \frac{\frac{5v}{6}}{\frac{3v}{4}}v = \frac{10}{9}v$

Q. If a source emitting waves a velocity $v/4\ $ and the observer moves away from the source with a velocity v/6, the apparent frequency as heard by the observer will be (v=velocity of sound)

Explanation

Reviewed by Dr. Abubacker

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