Q. In two similar wires of tension 16 N and $T$, 3 beats are heard, then T=

A) 49 N
B) 25 N
C) 64 N
D) None of these
Explanation

(a) Here ,$T_{1} = 16\ N,\ T_{2} = ?$
As per the choice given, $T_{2} > T_{1}$
$\ \ \therefore n_{2} > n_{1},\ \left( n_{2} - n_{1} \right) = 3\ \ \ \ \ \ \ \ \ \ldots(i)$
As $n \propto \sqrt{T}$
$\therefore\ \ \frac{n_{2}}{n_{1}} = \sqrt{\frac{T}{16}} = \sqrt{\frac{T}{4}}$
If $n_{1}$ corresponds to $4:n_{2}$ corresponds to $3 + 4 = 7$, which is $\sqrt{T}$. Therefore, $T = 49\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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