Q. A string of linear density $0.2\ kgm^{- 1}$ is stretched with a force of 500 N. A transverse wave of length 4.0 m and amplitude $(1/\lambda)$ metre is traveling along. Then the speed of the wave is
A) $50ms^{- 1}$
B) $62.5ms^{- 1}$
C) $2500ms^{- 1}$
D) $12.5ms^{- 1}$
Explanation
(a) $v = \sqrt{\frac{T}{m}} = \sqrt{\frac{500}{0.2}} = 50ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.