(b) $n = \frac{1}{2l}\sqrt{\frac{T}{m}} \Rightarrow n_{1}l_{1} = n_{2}l_{2} = n_{3}l_{3} = k$
$l_{1} + l_{2} + l_{3} = l \Rightarrow \frac{k}{n_{1}} + \frac{k}{n_{2}} + \frac{k}{n_{3}} = \frac{k}{n}$
$\Rightarrow \frac{1}{n} = \frac{1}{n_{1}} + \frac{1}{n_{2}} + \frac{1}{n_{3}}$