Q. The equation of a simple harmonic wave is given by y=6sin 2$\ \pi$ (2t-0.1x), where x and y are in mm and t is in second. The phase difference between two particles 2 mm apart at any instant is
A) 18°
B) 36°
C) 54°
D) 72°
Explanation
(d) From the given equation k=0.2π
$\Longrightarrow \ \ \ \frac{2\pi}{\lambda} = 0.2\pi$
$\Longrightarrow \ \lambda = 10\ mm$
$\mathrm{\Delta}\Phi = \frac{2\pi}{\lambda} \times \mathrm{\Delta}x$
$= \frac{2\pi}{10} \times 2 = \frac{2\pi}{5} = 72{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.