Q.
Two waves are represented by $y_{1} = a\sin\left( \omega t + \frac{\pi}{6} \right)$ and $y_{2} = a\cos{\omega t.}$ What will be their resultant amplitude
A) $a$
B) $\sqrt{2}a$
C) $\sqrt{3}a$
D) $2a$
Explanation
(c) $A = \sqrt{(a_{1}^{2} + a_{2}^{2} + 2a_{1}a_{2}\cos\phi)}$
Putting $a_{1} = a_{2} = a$ and $\phi = \frac{\pi}{3},$ we get $A = \sqrt{3}a$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.