Q. A wave motion has the function $y = a_{0}\sin{(\omega t - kx)}.$ The graph in figure shows how the displacement $y$ at a fixed point varies with time $t.$ Which one of the labelled points shows a displacement equal to that at the position $x = \frac{\pi}{2k}$ at time $t = 0$

A) $P$
B) $Q$
C) $R$
D) $S$
Explanation

(b) At $t = 0$ and $x = \frac{\pi}{2k}.$ The displacement
$y = a_{0}\sin{\left( \omega x_{0} - k \times \frac{\pi}{2x} \right) = - a_{0}\sin{\frac{\pi}{2} = - a_{0}}}$
from graph. Point of maximum displacement $(a_{0})$ in negative direction is $Q$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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