(b) At $t = 0$ and $x = \frac{\pi}{2k}.$ The displacement
$y = a_{0}\sin{\left( \omega x_{0} - k \times \frac{\pi}{2x} \right) = - a_{0}\sin{\frac{\pi}{2} = - a_{0}}}$
from graph. Point of maximum displacement $(a_{0})$ in negative direction is $Q$