(b) Since, an open pipe produces both even and odd harmonics, hence frequency of pipe
$= 200 \pm 5$
=195 Hz or 205 Hz.
Frequency of second harmonic of pipe =2v.
Now, the number of beats=10
$\therefore\ \ 2v = 420 \pm 10 = 410\ Hz\ or\ 430\ Gz$
∴v=205 Hz or 215Hz.$\ $
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