Q. Standing waves are produced in a $10\ m$ long stretched string. If the string vibrates in 5 segments and the wave velocity is $20\ m/s,$ the frequency is
A) $2\ Hz$
B) $4\ Hz$
C) $5\ Hz$
D) $10\ Hz$
Explanation
(c) String vibrates in five segment so $\frac{5}{2}\lambda = l \Rightarrow \lambda = \frac{2l}{5}$
Hence $n = \frac{v}{\lambda} = 5 \times \frac{v}{2l} = 5 \times \frac{20}{2 \times 10} = 5\ Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.