Q. Tube A has both ends open while tube B has one end closed. Otherwise they are identical. Their fundamental frequencies are in the ratio
A) 4:1
B) 2:1
C) 1:4
D) 1:4
Explanation
(b) $\therefore\frac{v}{v_{c}} = \frac{c/2\lambda}{v/4\lambda} = \frac{2}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.