Q. A wave of frequency 500 Hz has a velocity$360ms^{- 1}$. The phase difference between two displacements at a certain point at a time $10^{- 3}$ s apart will be
A) $\pi\ rad$
B) $\frac{\pi}{2}rad$
C) $\frac{\pi}{4}rad$
D) $2\pi\ rad$
Explanation
(a) Here,$n = 500\ Hz,T = \frac{1}{n} = \frac{1}{500} = 2 \times 10^{- 3}\ s$
Phase difference corres to $2 \times 10^{- 3}\ s = 2\pi$ rad
Phase difference corres to
$1 = 10^{- 3} = \frac{2\pi \times 1 \times 10^{- 3}}{2 \times 10^{- 3}} = \pi$ rad
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.