A tuning fork of frequency 480 Hz produces 10 beats $s^{- 1}$ when sounded with a vibrating sonometer string. What must have been the frequency of string if slight increase in tension produces fewer beats $s^{- 1}$ than before?

Question

Dr. Abubacker · Accepted Answer

(b) Here $n_{1} = 480,m = 10$
$n_{2} = n_{1} \pm m = 480 \pm 10 = 490\ or\ 470$
When tension is increased, $n_{2}$ will increase
$(	herefore n_{2} \propto \sqrt{T})$.
As number of beats $s^{- 1}$ decrease, $n_{2} = 470\ Hz$

Q. A tuning fork of frequency 480 Hz produces 10 beats $s^{- 1}$ when sounded with a vibrating sonometer string. What must have been the frequency of string if slight increase in tension produces fewer beats $s^{- 1}$ than before?

Explanation

Reviewed by Dr. Abubacker

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