(d) $v = \sqrt{\frac{\gamma RT}{M}} \Rightarrow \frac{T_{N}}{T_{0}} = \frac{M_{N}}{M_{0}} \Rightarrow \frac{T_{N}}{273 + 55} = \frac{14}{16} = \frac{7}{8}$ $\Rightarrow T_{N} = 287K = 14℃$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.