With what velocity should an observer approach stationary sound source, so that apparent frequency of sound should appear double the actual frequency? (v is velocity of sound)

Question

Dr. Abubacker · Accepted Answer

(d) By using
$v^{'} = v\left\lbrack \frac{v - v_{o}}{v - v_{s}} \right\rbrack$
$2v = v\left\lbrack \frac{v - v}{v - 0} \right\rbrack$
$\Longrightarrow v_{o} = - v$
Negative sign indicates that observer is moving opposite to the direction of velocity of sound.

Q. With what velocity should an observer approach stationary sound source, so that apparent frequency of sound should appear double the actual frequency? (v is velocity of sound)

Explanation

Reviewed by Dr. Abubacker

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