Q. Two stretched strings have length π and 2π while tensions are T and 4T respectively. If they are made of same material the ratio of their frequencies is
A) 2:1
B) 1:2
C) 1:1
D) 1:4
Explanation
(c) Frequency is given by
$v = \frac{1}{l}\sqrt{\frac{T}{\mu}}\ $
β΄first frequency
$v_{1} = \frac{1}{2l}\sqrt{\frac{T}{\mu}}$
And second frequency
$v_{2} = \frac{1}{4l}\sqrt{\frac{4T}{\mu}}$
β΄hence, the ratio of frequencies
$\frac{v_{1}}{v_{2}} = 1:1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.