
(c) Speed $= n\lambda = n(4ab) = 4n \times ab\ \ \ \left\lbrack As\ ab = \frac{\lambda}{4} \right\rbrack$
Path difference between $b$ and $e$ is $\frac{3\lambda}{4}$
So the phase difference $= \frac{2\pi}{\lambda}.$ Path difference
$= \frac{2\pi}{\lambda}.\frac{3\lambda}{4} = \frac{3\pi}{2}$