Q. Two sound waves are represented by $y = a\ sin(\omega t - kx)\ $ and$y = a\ cos(\omega t - kx)$. The wavelength of wave I water are
A) $\frac{\pi}{2}$
B) $\frac{\pi}{4}$
C) $\pi$
D) $\frac{3\pi}{4}$
Explanation
(a) As$\sin{(90 \pm \theta = \cos\theta)}$, therefore, phase difference between the two waves is$\ 90{^\circ}\ or\ \frac{\pi}{2}$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.