Q. A sound source is moving towards stationary listener with $\frac{1}{10}$th of the speed of sound. The ratio of apparent to real frequency is

A) $\left( \frac{9}{10} \right)^{2}$
B) 10/9
C) 11/10
D) $\left( \frac{11}{10} \right)^{2}$
Explanation

(b) Given,
$v_{s} = \frac{v}{10}$
Apparent frequency
$v’ = v\left( \frac{v}{v - v_{s}} \right)$
Where
v=real frequency of source
v=velocity of sound
$v_{s}$=velocity of source
So,
$\frac{v^{'}}{v^{'}} = \frac{v}{v - \frac{v}{10}} = \frac{10}{9}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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