Two progressive waves having equation $x_{1} = 3$ sin $\omega t$ and $x_{2} = 4\sin(\omega t - 90{^\circ})$ are superimposed. The amplitude of the resultant wave is

Question

Dr. Abubacker · Accepted Answer

(a) Given, $x_{1} = 3\sin{\omega t}$
$and\ \ \ \ x_{2} = 4\sin(\omega t - 90{^\circ})$
The phase difference between the two waves is 90°.
So, resultant amplitude
$a = \sqrt{(3)^{2} + (4)^{2}}$
$= \sqrt{9 + 16} = \sqrt{25}$
= 5 unit

Q. Two progressive waves having equation $x_{1} = 3$ sin $\omega t$ and $x_{2} = 4\sin(\omega t - 90{^\circ})$ are superimposed. The amplitude of the resultant wave is

Explanation

Reviewed by Dr. Abubacker

Want more practice?