Q. In the 3$^{rd}$ overtone of an open organ pipe, there are ($N$-stands for nodes and $A$-for antinodes )

A) $2N,\ 3A$
B) $3N,\ 4A$
C) $4N,\ 5A$
D) $5N,\ 4A$
Explanation

(c) In open organ pipe 3$^{rd}$ overtone corresponds to 4$^{th}$ harmonic mode.
Also in open pipe, Number of nodes = Order of mode of vibration and number of antinodes = (Number of nodes + 1). Here number of nodes $= 4,$ Number of antinodes $= 4 + 1 = 5$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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