Q. In a resonance tube, using a tuning fork of frequency 325 Hz, two successive resonance length are observed as 25.4 cm and 77.4 cm respectively. The velocity of sound in air is

A) $338ms^{- 1}$
B) $328ms^{- 1}$
C) $330ms^{- 1}$
D) $320ms^{- 1}$
Explanation

(a) $v = 2n\left( l_{2} - l_{1} \right) = 2 \times 325(77.4 - 25.4)cms^{- 1}$
$= \frac{650 \times 52}{100}\ ms^{- 1} = 338\ ms^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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