Equation of motion in the same direction is given by $y_{1} = A\sin{(\omega t - kx)}$, $y_{2} = A\sin{(\omega t - kx - heta).}$ The amplitude of the medium particle will be

Question

Equation of motion in the same direction is given by $y_{1} = A\sin{(\omega t - kx)}$, $y_{2} = A\sin{(\omega t - kx - 	heta).}$ The amplitude of the medium particle will be

Dr. Abubacker · Accepted Answer

(a) The resultant amplitude is given by
$A_{R} = \sqrt{A^{2} + A^{2} + 2AA\cos	heta} = \sqrt{2A^{2}(1 + \cos	heta)}$
$= 2A\cos{	heta/2}\ \ \ \ \ \ \ (\because 1 + \cos{	heta = 2\cos^{2}{	heta/2}})$

Q. Equation of motion in the same direction is given by $y_{1} = A\sin{(\omega t - kx)}$, $y_{2} = A\sin{(\omega t - kx - \theta).}$ The amplitude of the medium particle will be

Explanation

Reviewed by Dr. Abubacker

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