Q. A long cylindrical tube carries a highly polished piston and has a side opening. A tuning fork of frequency n is sounded at the sound heard by the listener charges if the piston is moves in or out. At a particular position of the piston is moved through a distance of 9 cm, the intensity of sound becomes minimum, if the speed of sound is 360 m/s, the value of n is

A) 129.6 Hz
B) 500 Hz
C) 1000 Hz
D) 2000 Hz
Explanation

(c) When piston moves a distance$x_{1}$, path difference change by 2 xs.
$\therefore$the path difference between maxima and consecutive minima=$\lambda/2$
∴$2x = \lambda/2$
Or
λ=4x=4×9 cm=36cm=0.36m
$n = \frac{v}{\lambda} = \frac{360}{0.36} = 1000\ Hz$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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