
(c) When piston moves a distance$x_{1}$, path difference change by 2 xs.
$\therefore$the path difference between maxima and consecutive minima=$\lambda/2$
∴$2x = \lambda/2$
Or
λ=4x=4×9 cm=36cm=0.36m
$n = \frac{v}{\lambda} = \frac{360}{0.36} = 1000\ Hz$