Q. If the wave equation $y = 0.08\sin{\frac{2\pi}{\lambda}(200t - x)}$ then the velocity of the wave will be
A) $400\sqrt{2}$
B) $200\sqrt{2}$
C) 400
D) 200
Explanation
(d) Comparing with standard wave equation
$y = a\sin{\frac{2\pi}{\lambda}(vt - x),}$ we get$,\ v = 200\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.