Q. 50 tuning forks are arranged in increasing order of their frequencies such that each gives 4 beats/sec with its previous tuning fork. If the frequency of the last fork is octave of the first, then the frequency of the frequency of the first tuning fork is
A) $200\ Hz$
B) $204\ Hz$
C) $196\ Hz$
D) None of these
Explanation
(c) Frequencies of tuning forks is given by
$n_{last} = n_{first} + (N - 1)x$
$2n = n + (50 - 1) \times 4 \Rightarrow n = 196Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.