A source and an observer move away from each other with a velocity of $10\ m/s$ with respect to ground. If the observer finds the frequency of sound coming from the source as $1950\ Hz,$ then actual frequency of the source is (velocity of sound in air $= 340\ m/s$)

Question

Dr. Abubacker · Accepted Answer

(b) $n^{'} = n\left( \frac{v - v_{O}}{v + v_{S}} \right) = n\left( \frac{340 - 10}{340 + 10} \right) = 1950$
$\Rightarrow n = 2068\ Hz$

Q. A source and an observer move away from each other with a velocity of $10\ m/s$ with respect to ground. If the observer finds the frequency of sound coming from the source as $1950\ Hz,$ then actual frequency of the source is (velocity of sound in air $= 340\ m/s$)

Explanation

Reviewed by Dr. Abubacker

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