Q. The frequency of the fundamental note in a wire stretched under tension T is v. if the tension is increased to 25T, then the frequency of the fundamental note will be

A) 25v
B) 5v
C) 10v
D) V
Explanation

(b) The fundamental frequency
$v = \frac{1}{2L}\sqrt{\frac{T}{m}}$
$\therefore\ \ \ \frac{v^{'}}{v} = \sqrt{\frac{T^{'}}{T}} = \sqrt{\frac{25T}{T}} = 5$
Or $v^{'} = 5v$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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