The displacement $x$(in meter) of a particle performing simple harmonic, motion is related to time t (in second) as $x = 0.05\cos\left( 4\pi t + \frac{\pi}{4} \right)$.The frequency of the motion will be

Question

Dr. Abubacker · Accepted Answer

(d) Compare the given equation with the standard form
$y = r\cos\left\lbrack \frac{2\pi t}{T} - \frac{2\pi x}{\lambda} \right\rbrack$
Coefficient of $t = \frac{2\pi}{T} = 2\pi n = 4\pi,n = 2\ Hz$

Q. The displacement $x$(in meter) of a particle performing simple harmonic, motion is related to time t (in second) as $x = 0.05\cos\left( 4\pi t + \frac{\pi}{4} \right)$.The frequency of the motion will be

Explanation

Reviewed by Dr. Abubacker

Want more practice?