Q. Stationary waves are set up in air column. Velocity of sound in air is $330\ m/s$ and frequency is $165\ Hz.$ Then distance between the nodes is
A) $2\ m$
B) $1\ m$
C) $0.5\ m$
D) $4\ m$
Explanation
(b) $v = 330\ m/s;n = 165\ Hz.$ Distance between two successive nodes
$= \frac{\lambda}{2} = \frac{v}{2n} = \frac{330}{2 \times 165} = 1m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.