Q. If the equation of transverse wave is $y = 5\sin{2\pi\left\lbrack \frac{t}{0.04} - \frac{x}{40} \right\rbrack,}$ where distance is in $cm$ and time in second, then the wavelength of the wave is

A) $60\ cm$
B) $40\ cm$
C) $35\ cm$
D) $25\ cm$
Explanation

(b) Comparing with $y = a\sin{2\pi\left\lbrack \frac{t}{T} - \frac{x}{\lambda} \right\rbrack \Rightarrow \lambda = 40\ cm}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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