Two closed pipes produce 10 beats per second when emitting their fundamental nodes. If their lengths are in ratio of 25 : 26. Then their fundamental frequency in $Hz,$ are

Question

Dr. Abubacker · Accepted Answer

(c) $n_{1} - n_{2} = 10$ …(i)
Using $n_{1} = \frac{v}{4l_{1}}$ and $n_{2} = \frac{v}{4l_{2}}$
$\Rightarrow \frac{n_{1}}{n_{2}} = \frac{l_{2}}{l_{1}} = \frac{26}{25}$ …(ii)
After solving these equation $n_{1} = 260\ Hz,\ n_{2} = 250\ Hz$

Q. Two closed pipes produce 10 beats per second when emitting their fundamental nodes. If their lengths are in ratio of 25 : 26. Then their fundamental frequency in $Hz,$ are

Explanation

Reviewed by Dr. Abubacker

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