Q. Three waves of equal frequency having amplitudes 10 mm, 4 mm, and 7 mm arrive at a given point with successive phase difference of $\frac{\pi}{2}$ , the amplitude of the resulting wave in mm is given by

A) 7
B) 6
C) 5
D) 4
Explanation

(c) As phase difference between waves of amplitudes $10\ mm$ and $7\ mm$ is $\pi$, therefore, their resultant amplitude $= 10 - 7 = 3\ mm$. Now amplitudes $3\ mm$ and $4\ mm$ have a phase difference$\ = \frac{\pi}{2}$.
$\therefore$ Resultant amplitude $= \sqrt{3^{2} + 4^{2}} = 5\ mm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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